Passay 简明教程

Passay - LengthComplexityRule

LengthComplexityRule 有助于根据密码长度定义其适用的规则。请考虑以下策略。

LengthComplexityRule helps in defining the applicable rule on a password based on its length. Consider the following policy.

  1. If length of password is in between 1 to 5 characters, only lower case alphabets are allowed.

  2. If length of password is in between 6 to 8 characters, then only a, b and c are allowed.

Example

以下示例显示了使用 Passay 库根据上述策略对密码进行验证的过程。

The below example shows the validation of a password against above policy using Passay library.

import org.passay.AllowedCharacterRule;
import org.passay.CharacterRule;
import org.passay.EnglishCharacterData;
import org.passay.LengthComplexityRule;
import org.passay.PasswordData;
import org.passay.PasswordValidator;
import org.passay.RuleResult;

public class PassayExample {
   public static void main(String[] args) {
      LengthComplexityRule lengthComplexityRule = new LengthComplexityRule();
      //Rule: Password of 1 to 5 characters should contains lower case alphabets only
      lengthComplexityRule.addRules("[1,5]",
         new CharacterRule(EnglishCharacterData.LowerCase, 5));
      //8 and 16 characters
      lengthComplexityRule.addRules("[6,8]",
         new AllowedCharacterRule(new char[] { 'a', 'b', 'c' }));
      PasswordValidator validator = new PasswordValidator(lengthComplexityRule);
      PasswordData password = new PasswordData("abcdef");
      RuleResult result = validator.validate(password);
      if(result.isValid()){
         System.out.println("Password validated.");
      }else{
         System.out.println("Invalid Password: " + validator.getMessages(result));
      }
   }
}

Output

Invalid Password: [
Password contains the illegal character 'd'.,
Password contains the illegal character 'e'.,
Password contains the illegal character 'f'.,
Password meets 0 complexity rules, but 1 are required.]