Servlets 简明教程
Servlets - File Uploading
Servlet 可以与 HTML 表单标记一起使用,允许用户将文件上载到服务器。上传的文件可以是文本文件、图像文件或任何文档。
A Servlet can be used with an HTML form tag to allow users to upload files to the server. An uploaded file could be a text file or image file or any document.
Creating a File Upload Form
以下 HTM 代码创建一个上传程序表单。以下是需要注意的重要事项:
The following HTM code below creates an uploader form. Following are the important points to be noted down −
-
The form method attribute should be set to POST method and GET method can not be used
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The form enctype attribute should be set to multipart/form-data.
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The form action attribute should be set to a servlet file which would handle file uploading at backend server. Following example is using UploadServlet servlet to upload file.
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To upload a single file you should use a single <input …/> tag with attribute type="file". To allow multiple files uploading, include more than one input tags with different values for the name attribute. The browser associates a Browse button with each of them.
<html>
<head>
<title>File Uploading Form</title>
</head>
<body>
<h3>File Upload:</h3>
Select a file to upload: <br />
<form action = "UploadServlet" method = "post" enctype = "multipart/form-data">
<input type = "file" name = "file" size = "50" />
<br />
<input type = "submit" value = "Upload File" />
</form>
</body>
</html>
这将显示以下结果,该结果允许从本地 PC 中选择一个文件,当用户单击“上传文件”时,表单将与所选文件一起提交:
This will display following result which would allow to select a file from local PC and when user would click at "Upload File", form would be submitted along with the selected fil −
File Upload:
Select a file to upload:
NOTE: This is just dummy form and would not work.
Writing Backend Servlet
以下是 UploadServlet servlet,它将负责接受上传的文件并将其存储在目录 <Tomcat-installation-directory>/webapps/data 中。此目录名称还可以使用外部配置(例如 web.xml 中的 context-param 元素)如下所示添加:
Following is the servlet UploadServlet which would take care of accepting uploaded file and to store it in directory <Tomcat-installation-directory>/webapps/data. This directory name could also be added using an external configuration such as a context-param element in web.xml as follows −
<web-app>
....
<context-param>
<description>Location to store uploaded file</description>
<param-name>file-upload</param-name>
<param-value>
c:\apache-tomcat-5.5.29\webapps\data\
</param-value>
</context-param>
....
</web-app>
以下是 UploadServlet 的源代码,它可以一次处理多个文件上传。在继续之前,请确保以下内容:
Following is the source code for UploadServlet which can handle multiple file uploading at a time. Before proceeding you have make sure the followings −
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Following example depends on FileUpload, so make sure you have the latest version of commons-fileupload.x.x.jar file in your classpath. You can download it from https://commons.apache.org/fileupload/.
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FileUpload depends on Commons IO, so make sure you have the latest version of commons-io-x.x.jar file in your classpath. You can download it from https://commons.apache.org/io/.
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While testing following example, you should upload a file which has less size than maxFileSize otherwise file would not be uploaded.
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Make sure you have created directories c:\temp and c:\apache-tomcat8.0.28\webapps\data well in advance.
// Import required java libraries
import java.io.*;
import java.util.*;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.io.output.*;
public class UploadServlet extends HttpServlet {
private boolean isMultipart;
private String filePath;
private int maxFileSize = 50 * 1024;
private int maxMemSize = 4 * 1024;
private File file ;
public void init( ){
// Get the file location where it would be stored.
filePath = getServletContext().getInitParameter("file-upload");
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
// Check that we have a file upload request
isMultipart = ServletFileUpload.isMultipartContent(request);
response.setContentType("text/html");
java.io.PrintWriter out = response.getWriter( );
if( !isMultipart ) {
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet upload</title>");
out.println("</head>");
out.println("<body>");
out.println("<p>No file uploaded</p>");
out.println("</body>");
out.println("</html>");
return;
}
DiskFileItemFactory factory = new DiskFileItemFactory();
// maximum size that will be stored in memory
factory.setSizeThreshold(maxMemSize);
// Location to save data that is larger than maxMemSize.
factory.setRepository(new File("c:\\temp"));
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
// maximum file size to be uploaded.
upload.setSizeMax( maxFileSize );
try {
// Parse the request to get file items.
List fileItems = upload.parseRequest(request);
// Process the uploaded file items
Iterator i = fileItems.iterator();
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet upload</title>");
out.println("</head>");
out.println("<body>");
while ( i.hasNext () ) {
FileItem fi = (FileItem)i.next();
if ( !fi.isFormField () ) {
// Get the uploaded file parameters
String fieldName = fi.getFieldName();
String fileName = fi.getName();
String contentType = fi.getContentType();
boolean isInMemory = fi.isInMemory();
long sizeInBytes = fi.getSize();
// Write the file
if( fileName.lastIndexOf("\\") >= 0 ) {
file = new File( filePath + fileName.substring( fileName.lastIndexOf("\\"))) ;
} else {
file = new File( filePath + fileName.substring(fileName.lastIndexOf("\\")+1)) ;
}
fi.write( file ) ;
out.println("Uploaded Filename: " + fileName + "<br>");
}
}
out.println("</body>");
out.println("</html>");
} catch(Exception ex) {
System.out.println(ex);
}
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
throw new ServletException("GET method used with " +
getClass( ).getName( )+": POST method required.");
}
}
}
Compile and Running Servlet
编译上述 servlet UploadServlet,并在 web.xml 文件中创建必需的条目,如下所示。
Compile above servlet UploadServlet and create required entry in web.xml file as follows.
<servlet>
<servlet-name>UploadServlet</servlet-name>
<servlet-class>UploadServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>UploadServlet</servlet-name>
<url-pattern>/UploadServlet</url-pattern>
</servlet-mapping>
现在尝试使用您在上面创建的 HTML 表单上传文件。当您尝试 [role="bare"] [role="bare"]http://localhost:8080/UploadFile.htm 时,它将显示以下结果,这将帮助您上传本地计算机上的任何文件。
Now try to upload files using the HTML form which you created above. When you would try [role="bare"]http://localhost:8080/UploadFile.htm, it would display following result which would help you uploading any file from your local machine.
File Upload:
Select a file to upload:
如果您的 servlet 脚本运行良好,您的文件应上传到 c:\apache-tomcat-8.0.28\webapps\data\ 目录中。
If your servlet script works fine, your file should be uploaded in c:\apache-tomcat8.0.28\webapps\data\ directory.