Springmvc 简明教程

Spring MVC - Parameterizable View Controller Example

以下示例展示了如何使用Spring Web MVC框架的Multi Action Controller的参数化视图控制器方法。参数化视图允许使用请求映射网页。

The following example shows how to use the Parameterizable View Controller method of a Multi Action Controller using the Spring Web MVC framework. The Parameterizable View allows mapping a webpage with a request.

package com.tutorialspoint;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

public class UserController extends MultiActionController{

   public ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Home");
      return model;
   }
}
<bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
   <property name="mappings">
      <value>
         index.htm=userController
      </value>
   </property>
</bean>
<bean id="userController" class="org.springframework.web.servlet.mvc.ParameterizableViewController">
   <property name="viewName" value="user"/>
</bean>

例如，使用以上配置，如果URI。

For example, using the above configuration, if URI.

  1. /index.htm is requested, DispatcherServlet will forward the request to the UserController controller with viewName set as user.jsp.

首先，让我们建立一个可用的 Eclipse IDE，并遵循以下步骤，使用 Spring Web 框架开发一个基于动态表单的 Web 应用程序。

To start with it, let us have a working Eclipse IDE in place and stick to the following steps to develop a Dynamic Form based Web Application using Spring Web Framework.

Step

Description

1

Create a project with a name TestWeb under a package com.tutorialspoint as explained in the Spring MVC - Hello World chapter.

2

Create a Java class UserController under the com.tutorialspoint package.

3

Create a view file user.jsp under the jsp sub-folder.

4

The final step is to create the content of the source and configuration files and export the application as explained below.

UserController.java

package com.tutorialspoint;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.multiaction.MultiActionController;

public class UserController extends MultiActionController{

   public ModelAndView home(HttpServletRequest request,
      HttpServletResponse response) throws Exception {
      ModelAndView model = new ModelAndView("user");
      model.addObject("message", "Home");
      return model;
   }
}

TestWeb-servlet.xml

<beans xmlns = "http://www.springframework.org/schema/beans"
   xmlns:context = "http://www.springframework.org/schema/context"
   xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation = "
   http://www.springframework.org/schema/beans
   http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
   http://www.springframework.org/schema/context
   http://www.springframework.org/schema/context/spring-context-3.0.xsd">

   <bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
      <property name = "prefix" value = "/WEB-INF/jsp/"/>
      <property name = "suffix" value = ".jsp"/>
   </bean>

   <bean class = "org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
      <property name = "mappings">
         <value>
            index.htm = userController
         </value>
      </property>
   </bean>
   <bean id = "userController" class = "org.springframework.web.servlet.mvc.ParameterizableViewController">
      <property name = "viewName" value="user"/>
   </bean>
</beans>

user.jsp

<%@ page contentType="text/html; charset=UTF-8" %>
<html>
   <head>
      <title>Hello World</title>
   </head>
   <body>
      <h2>Hello World</h2>
   </body>
</html>

一旦你创建完资源文件和配置文件，导出你的应用程序。右键点击你的应用程序，使用 Export → WAR File 选项并在Tomcat的webapps文件夹中保存 TestWeb.war 文件。

Once you are done with creating source and configuration files, export your application. Right click on your application, use Export → WAR File option and save the TestWeb.war file in Tomcat’s webapps folder.

现在，启动您的 Tomcat 服务器，并确保您可以使用标准浏览器从 Webapps 文件夹中访问其他网页。现在，尝试一个 URL – http://localhost:8080/TestWeb/index.htm ，如果 Spring Web 应用程序一切正常，您将看到以下屏幕。

Now, start your Tomcat server and make sure you are able to access other webpages from webapps folder using a standard browser. Now, try a URL – http://localhost:8080/TestWeb/index.htm and you will see the following screen, if everything is fine with the Spring Web Application.

spring multiaction controller3