Java Mysql 简明教程
Java & MySQL - Updating a ResultSet
ResultSet 接口包含一组用于更新结果集数据的更新方法。
与 get 方法类似,针对每种数据类型有两种更新方法:
-
一个接受列名称。
-
一个接受列索引。
例如,要更新结果集当前行的 String 列,将使用以下任一 updateString() 方法:
S.N. |
Methods & Description |
1 |
*public void updateString(int columnIndex, String s) throws SQLException*将指定列中的 String 更改为 s 的值。 |
2 |
*public void updateString(String columnName, String s) throws SQLException*与上一个方法类似,只是通过名称而不是索引指定列。 |
有用于八种原始数据类型以及 java.sql 包中的 String、Object、URL 和 SQL 数据类型的更新方法。
更新结果集中的行将更改 ResultSet 对象中当前行的列,但不会更改底层数据库中的内容。要更新对数据库中行的更改,需要调用以下任一方法。
S.N. |
Methods & Description |
1 |
*public void updateRow()*通过更新数据库中相应的行来更新当前行。 |
2 |
*public void deleteRow()*从数据库中删除当前行 |
3 |
*public void refreshRow()*刷新结果集中的数据以反映数据库中的任何近期更改。 |
4 |
*public void cancelRowUpdates()*取消对当前行进行的任何更新。 |
5 |
*public void insertRow()*将行插入数据库。只能在游标指向插入行时调用此方法。 |
以下是 Result Set 教程中描述的 ResultSet.CONCUR_UPDATABLE 和 ResultSet.TYPE_SCROLL_INSENSITIVE 示例。此示例将解释表上的 INSERT、UPDATE 和 DELETE 操作。
需要注意的是,您正在处理的表应该正确设置了主键。让我们首先更新参照表。
删除表并按照如下方法重新创建表 Employees :
mysql> use TUTORIALSPOINT;
mysql> drop table Employees;
Query OK, 0 rows affected (0.08 sec)
mysql> create table Employees
-> (
-> id int primary key auto_increment,
-> age int not null,
-> first varchar (255),
-> last varchar (255)
-> );
Query OK, 0 rows affected (0.08 sec)
mysql>
Create Data Records
最后,在 Employee 表中创建一些记录,如下所示 −
mysql> INSERT INTO Employees(AGE, FIRST, LAST) VALUES (18, 'Zara', 'Ali');
Query OK, 1 row affected (0.05 sec)
mysql> INSERT INTO Employees(AGE, FIRST, LAST) VALUES (25, 'Mahnaz', 'Fatma');
Query OK, 1 row affected (0.00 sec)
mysql> INSERT INTO Employees(AGE, FIRST, LAST) VALUES (30, 'Zaid', 'Khan');
Query OK, 1 row affected (0.00 sec)
mysql> INSERT INTO Employees(AGE, FIRST, LAST) VALUES (28, 'Sumit', 'Mittal');
Query OK, 1 row affected (0.00 sec)
mysql>
将以下示例复制并粘贴到 TestApplication.java 中,如下进行编译和运行:
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.sql.Statement;
public class TestApplication {
static final String DB_URL = "jdbc:mysql://localhost/TUTORIALSPOINT";
static final String USER = "guest";
static final String PASS = "guest123";
static final String QUERY = "SELECT id, first, last, age FROM Employees";
public static void printResultSet(ResultSet rs) throws SQLException{
// Ensure we start with first row
rs.beforeFirst();
while(rs.next()){
// Display values
System.out.print("ID: " + rs.getInt("id"));
System.out.print(", Age: " + rs.getInt("age"));
System.out.print(", First: " + rs.getString("first"));
System.out.println(", Last: " + rs.getString("last"));
}
System.out.println();
}
public static void main(String[] args) {
// Open a connection
try(Connection conn = DriverManager.getConnection(DB_URL, USER, PASS);
Statement stmt = conn.createStatement(
ResultSet.TYPE_SCROLL_INSENSITIVE,
ResultSet.CONCUR_UPDATABLE);
ResultSet rs = stmt.executeQuery(QUERY);
) {
System.out.println("List result set for reference....");
printResultSet(rs);
// Loop through result set and add 5 in age
// Move to Before first position so while-loop works properly
rs.beforeFirst();
//STEP 7: Extract data from result set
while(rs.next()){
// Retrieve by column name
int newAge = rs.getInt("age") + 5;
rs.updateDouble( "age", newAge );
rs.updateRow();
}
System.out.println("List result set showing new ages...");
printResultSet(rs);
// Insert a record into the table.
// Move to insert row and add column data with updateXXX()
System.out.println("Inserting a new record...");
rs.moveToInsertRow();
rs.updateString("first","John");
rs.updateString("last","Paul");
rs.updateInt("age",40);
// Commit row
rs.insertRow();
System.out.println("List result set showing new set...");
printResultSet(rs);
} catch (SQLException e) {
e.printStackTrace();
}
}
}
现在让我们如下编译上述示例:
C:\>javac TestApplication.java
C:\>
运行 TestApplication 时,它会生成以下结果:
C:\>java TestApplication
List result set for reference....
ID: 1, Age: 18, First: Zara, Last: Ali
ID: 2, Age: 25, First: Mahnaz, Last: Fatma
ID: 3, Age: 30, First: Zaid, Last: Khan
ID: 4, Age: 28, First: Sumit, Last: Mittal
List result set showing new ages...
ID: 1, Age: 23, First: Zara, Last: Ali
ID: 2, Age: 30, First: Mahnaz, Last: Fatma
ID: 3, Age: 35, First: Zaid, Last: Khan
ID: 4, Age: 33, First: Sumit, Last: Mittal
Inserting a new record...
List result set showing new set...
ID: 1, Age: 23, First: Zara, Last: Ali
ID: 2, Age: 30, First: Mahnaz, Last: Fatma
ID: 3, Age: 35, First: Zaid, Last: Khan
ID: 4, Age: 33, First: Sumit, Last: Mittal
ID: 5, Age: 40, First: John, Last: Paul
C:\>